A line equivalent to the x-axis is called a horizontal line. y=c is the equation of a horizontal line, where c is stable. The equations of the horizontal axis: y=0 and the equation of the vertical axis: x=0. Purpose of the function is invective is complete by the using horizontal line on solving horizontal.

Horizontal asymptotes are horizontal lines that the diagram of the task approaches as x tends s to +∞ or −∞. Vertical asymptotes are straight lines close to which the function raises without bounce.

Horizontal line equations are very simple to imagine and to recognize. Now we identify that a linear equation is of form:

**Y = aX + b.**

Where a is known as angle of the line and b is known as y intercept or the point where line slashes the y axis. For horizontal line the angle will be zero as it is similar to x axis and this horizontal line might slash at a point lets say at y = k where k is stable numbers like -2,-1,0,1,2,3 etc. k may be any real number. So the horizontal line equation will be of form Y = 0X + k or Y = k on solving horizontal.

**Horizontal asymptote of a function for solving horizontal:**

Rational function f(x) is the single which can be written in form of division of two functions p(x) / q(x). We consider degree of numerator as 'n' and degree of denominator as ’d’ and evaluate degrees of the task to resolve our horizontal asymptotes. Leading coefficients are coefficients of highest degree x in the function on solving horizontal.

1) Draw a horizontal asymptotes for given equation f(x) = (2x^{2} + 5) / (3x^{2}+7x+4), on solving horizontal.

**Solution:**

To graph this line now sketch a line passing during y = 4 and corresponding to x axis, the following shows that,

**
**

Here we observe, n=m so Horizontal Asymptote = ratio of leading coefficients of both functions. Thus, leading coefficient of p(x) i.e. numerator is 2 and leading coefficient of q(x) i.e. denominator is 3, so our Horizontal Asymptote will be y=2/3 and another time we notice here that arc is passage the horizontal asymptote.

2) Draw a graph of line y = 4 on the solving horizontal.

**Solution:**

To graph this line now sketch a line passing through y = 4 and corresponding to x axis, the following shows that,